The question is incomplete. Here is the complete question.
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.
a) Determine the arc length to the nearest tenth of an inch.
b) Explain why the following proportion would solve for the length of AC below: 
c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.
Note: The image in the attachment shows the arc to solve this question.
Answer: a) 9.4 in
c) x = 13.6 in
Step-by-step explanation:
a)
, where:
r is the radius of the circumference
mAB is the angle of the arc
arc length = 
arc length = 
arc length = 9.4
The arc lenght for the image is 9.4 inches.
b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):


c) Resolving (b):
x = 
x = 13.6
The arc length for the image is 13.6 inches.
-5, you never want the denominator to equal zero or else it doesnt exist!
x+5=0
x=-5
Answer:
40
Step-by-step explanation:
FAC = FAE + EAD +CAD
We know FAC = 180 and CAD = 50 and EAD = 90
180 = FAE + 90 +50
Combine like terms
180 = FAE + 140
Subtract 140 from each side
180-140 = FAE +140-140
40 = FAE
C=2pir, so take half of 15 which is 7.5 and plug it in as r and you get 47.12. Or just look up circumference calculator on google.