Answer:
H0: p(1980) = p(2010) ; H1 : P(1980) > P(2010)
0.02
Step-by-step explanation:
Given that:
Sample size in both 1980 and 2010 = 1000 samples :
Proportion in favor :
P(1980) = 0.66
P(2010) = 0.64
To test the hypothesis :
Null hypothesis :
Proportion in favor are the same in both years
Null hypothesis = H0 = p(1980) = p(2010)
Alternative hypothesis :
Proportion in favor in 1980 is greater than that in 2010
Alternative hypothesis = H1 : P(1980) > P(2010)
The sample statistic :
P(1980) - p(2010)
0.66 - 0.64
= 0.02
Answer:
4, -2
Step-by-step explanation:
1+1=2
2-2=0
0+3=3
so on
+1,-2,+3,-4,+5,-6...
M=-1
4m+2(m+1)=9m +5
4m+2m+2=9m+5
6m+2=9m+5
6m+2-6m= 9m+5-6m
2-5=3m+5-5
-3/3=3m/3
m=-1
34 + x = 63
x = 63-34
x = 29