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3 years ago

I don’t understand it

Mathematics

1 answer:

Serga [27]3 years ago

7 0

the balloon starts at 158 thats our set number

then it goes up 56 feet a minute, you add that to your height

after that you have the variables h and t you would write it as

h= 56t+ 158

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What is the distance between the points (-4,-8) and (10,-8)?

ioda

Answer: 14

Step-by-step explanation:

Input Data :

Point 1 ( x A , y A ) = (-4, -8)

Point 2 ( x B , y B ) = (10, -8)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √ (x B − x A ) 2 + ( y B − y A ) 2

Solution :

Distance between two points = √ ( 10 − − 4 ) 2 + ( − 8 − − 8 ) 2

= √ 14 ^2 + 0 ^2

= √ 196 + 0

= √ 196 = 14

Distance between points (-4, -8) and (10, -8) is 14

7 0

3 years ago

Substitute (= 3 and 1-6 to determine if the two expressions are equivalent.

mezya [45]

Answer:a b d

Step-by-step explanation:

4 0

3 years ago

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

5 0

3 years ago

Read 2 more answers

Pls help I need this done asap

Paul [167]

Answer:

I can help you solve this.

but first telll me in the comments what is the formula for this equation and ill tell u from there

5 0

3 years ago

What is the range of this function?

tigry1 [53]

I think it’s B but I dint really know

4 0

3 years ago