First, let's calculate how much money was deposited into his account.
33 × $348 = $11,484
Now, let's add that to his original amount of money in his account.
$11,484 + $1,618 = $<span>13,102
</span>
Next, let's calculate how much money was withdrawn from the account.
36 × $16 = $576
Now, you would subtract that from the account balance.
$13,102 - $576 = $<span>12,526
</span>
Then, you would add the deposit from his uncle to his account balance.
$12,526 + $261 = $<span>12,787
</span>
The last step would be to subtract the money for the bike.
$12,787 - $190 = $<span>12,597
</span>
Justin has $12,597 in his bank account.
I hope this helps! (Sorry to post this so late, my computer died before I could finish.)
Answer:
see below
Step-by-step explanation:
f(x) = −16x^2 + 22x + 3
Factor out the negative
f(x) = -( 16x^2 -22x -3)
= -(8x+1)(2x-3)
Find the x intercepts
Set y = 0
0 = -(8x+1)(2x-3)
Using the zero product property
8x+1 =0 2x-3 = 0
8x = -1 2x = 3
x = -1/8 x =3/2
The x intercepts are ( -1/8, 0) and ( 3/2, 0)
The end behavior
-16 x^2 is the dominate term
Let x →-∞
f(-∞) = -16 (-∞)^2 = -16 (∞) = -∞
As x goes to negative infinity y goes to - infinity
Let x →∞
f(∞) = -16 (∞)^2 = -16 (∞) = -∞
As x goes to infinity y goes to - infinity
We know this is a downward facing parabola a < 0 and this is a quadratic
We have the x intercepts
We can find the axis of symmetry from the zeros
(-1/8+ 3/2) /2 = (-1/8 + 12/8)/2 = (11/8)/2 = 11/6
The axis of symmetry is x = 11/16
Using the axis of symmetry and the equation, we can find the maximum point
y = -(8*11/16+1)(2*11/16-3) = 169/16
The vertex is at (11/16, 169/16(
Answer:
To find the horizontal asymptote, we note that the degree of the numerator is one and the degree of the denominator is two. Since the larger degree occurs in the denominator, the graph will have a horizontal asymptote at y = 0 (i.e., the x-axis). The vertical asymptotes will occur at those values of x for which the denominator is equal to zero.
Step-by-step explanation:
Answer:
oh my- this actually made me happy-
Step-by-step explanation:
I looked it up and got this........
What is 260 rounded to the nearest ten?
Here we will tell you what 260 is rounded to the nearest ten and also show you what rules we used to get to the answer. First, 260 rounded to the nearest ten is:
260
Remember, we did not necessarily round up or down, but to the ten that is nearest to 260.
When rounding to the nearest ten, like we did with 260 above, we use the following rules:
A) We round the number up to the nearest ten if the last digit in the number is 5, 6, 7, 8, or 9.
B) We round the number down to the nearest ten if the last digit in the number is 1, 2, 3, or 4.
C) If the last digit is 0, then we do not have to do any rounding, because it is already to the ten.
