Two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube. One particle tra
vels 97 cm in the 1st 2 seconds, 93 cm in next 2 seconds , 89 cm in another next 2 seconds, etc. The other particle travels 49 cm in the 1st 2 seconds, 47 cm in the next 2 seconds , 45 cm in another next 2 seconds, etc. Find how long it takes for the particles to meet and hence, determine the distances travelled by each particle
The problem with this question is that it is missing an important number, which is the length of the tube. Assuming that the tube is 10 meters long (=1,000 centimeters long)
time (in distance traveled distance traveled distance
seconds) by particle A in cms by particle B in cms between both
particles in cms
1 97 49 854
2 93 47 714
3 89 45 580
4 85 43 452
5 81 41 330
6 77 39 214
7 73 37 104
8 69 35 0
After 8 seconds both particles should meet. Particle A traveled 664 centimeters and particle B traveled 336 centimeters
First you take 8 common which is the highest number that can divide both the nimbers, then u can also take t common...now taking a negative common is up to you. so I did all this in the second step. Then you just set it equal to 0. t=0 and 15/2
