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il63 [147K]
3 years ago
6

DNA encodes the information necessary to produce the proteins needed by your body. To make these proteins, DNA first undergoes a

process known as transcription. This is when the information on a DNA strand is transferred to a molecule very similar to DNA, known as _______ .
Biology
2 answers:
oee [108]3 years ago
7 0
<h3><u>Answer; </u></h3>

Messenger RNA (mRNA)

<h3><u>Explanation;</u></h3>
  • DNA encodes the information necessary to produce the proteins needed by your body. To make these proteins, DNA first undergoes a process known as transcription.
  • <em><u>Transcription is the process that takes place in the nucleus of  a cell, where the information on the DNA strand is transferred to a molecules known as mRNA. This process iscatalyzed by the enzyme RNA polymerase.</u></em>
  • <em><u>The mRNA is a type of RNA which carries the information from the DNA for protein synthesis. The mRNA moves from the nucleus to the cytoplasm to special organelles called ribosomes where proteins are synthesized. </u></em>The process of synthesis is called<em><u> translation</u></em> which involves decoding the information carried by the mRNA to synthesis proteins.

anygoal [31]3 years ago
5 0
The answer to your blank space would be RNA! 

After transcription, the new single stranded RNA is now mRNA (messenger RNA) 
Hope I answered your question! :)

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Sergio [31]

Answer:

Explanition:

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4 0
3 years ago
If the DNA nucleotides read 3'-ATG-CGT-GAC-5', the amino acid sequence of the resulting polypeptide
Marat540 [252]

Answer:

5’ – TAC-GCA-CTG-3’

Explanation:

As per the Chargaff’s complementary base pairing rule purine always pairs with a pyrimidine.  

Purines include adenine (A) and cytosine (C)

Pyrimidine include thymine (T) and guanine (G)

Thus an A always pair with T and C always pair with G

Thus, the resulting poly peptide for the given amino acid sequence is  

3'-ATG-CGT-GAC-5'

5’ – TAC-GCA-CTG-3’

4 0
3 years ago
1) Glycogen phosphorylase catalyzes the removal of glucose from glycogen. The ∆G°’ for this reaction is 3.1 kJ/mole 1. Calculate
Andru [333]

Answer:

1. G° = -RT ln (G1P/P)

3.1 = 8.314 × 310 × ln (G1P/P)

3.1 / 2577.34 = ln (G1P/P)

0.0012 = ln (G1P/P)

0.0012 = (log G1P/P)/log 2.71828

0.4342 × 0.0012 = log G1P/P

0.00052 = log G1P/P

G1P/P = 10^0.00052 = 1.0012

P/G1P = 1/1.0012 = 0.9988

2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.  

Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.  

3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.  

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Answer: sheesh

Explanation cuz i said

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What is the density of each?
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This is the order from top to bottom rounded; 0.24, 0.28, 0.30, 0.33

7 0
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