The figures that can have a triangle as a two-dimensional cross section are (4) I, III, and IV, only
<h3>How to determine the figures?</h3>
The cross-section of three-dimensional figures are as a result of slicing the figure along its axis.
- When the cube is sliced with its plane, it gives a triangle face
- When a cone is sliced vertically, it gives a triangle face
- One of the faces of a square pyramid is a triangle; so it has a triangle face
Hence, the figures that can have a triangle as a two-dimensional cross section are (4) I, III, and IV, only
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First, solve for x. Isolate the x. Do the opposite of PEMDAS.
2x + 4 = 8
Note the equal sign. What you do to one side, you do to the other.
subtract 4 from both sides
2x + 4 (-4) = 8 (-4)
2x = 8 - 4
2x = 4
divide 2 from both sides
2x/2 = 4/2
x = 4/2
x = 2
you know you're starting number now: 2
"then add it to two": 2 + 2 = 4
"then add it to ten": 4 + 10 = 14
"then subtract three": 14 - 3 = 11
"then add ten": 11 + 10 = 21
21 is your final answer
hope this helps
Answer:
find the area of each figure
Answer:
2 angles have the same °
2 sides are the same length