Answer: B sorry if im wrong
Step-by-step explanation:
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
5 inch is the width, 8 inch is the length.
Find to scale between the two widths:
10 /5 = 2 the larger photo is 2 times larger,
Multiply the known length by 2:
8 x 2 = 16
The length would be 16
↝ x-intercept
↝ y-intercept
y = -5
↝ means that the shade/area is below the graph as shown in the first picture.
↝ x-intercept
↝ y-intercept
y = -3
↝ Since it's "≤" therefore. The shade/area is below the graph. For second picture.
First picture is first inequality
Second picture is second inequality.
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