An algebraic expression to represent the value of this car after M months is y=Mx+C.
We have given that the
The straight-line depreciation equation for a car is,
y = -2,680x + 26,800.
therefore after 4moths
y = -2,680(4) + 26,800.
y = -10720 + 26,800.
y=16080
<h3>
What is the slope?</h3>
The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)
b. For find after the 75 months replace x by 75 and slolve the given inequality.
Suppose that M represents the length of time in months when
the car still has value.
An algebraic expression to represent the value of this car after M months.
y=Mx+C.
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1 cm equals to 10 mm, therefore 7000 mm = 700 cm.
Yes 2x+13=21 is a linear equation
Answer: 2041 meters
A bicycle wheel is a circular object.
The circumference of a circle is 2π(radius)
Here given:
- radius = diameter/2 = 65/2 = 32.5 cm
Hence find the length for each revolution:
- 2π(32.5) = 204.1 cm per revolution
Then for 1000 revolutions:
- 204.1 × 1000 = 204100 cm ≈ 2041 meter
