1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pachacha [2.7K]
2 years ago
7

The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00

mole co2, 1.00 mole h2, 2.40 moles h2o, and 2.40 moles co. how many moles of co2 must be added to the system to bring the equilibrium co concentration to 0.791 mol/l? answer in units of moles.
Chemistry
1 answer:
Marina CMI [18]2 years ago
4 0

<u>Answer:</u> The moles of CO_2 added to the system is 7.13 moles

<u>Explanation:</u>

We are given:

Moles of CO_2 at equilibrium = 1.00 moles

Moles of H_2 at equilibrium = 1.00 moles

Moles of H_2O at equilibrium = 2.40 moles

Moles of CO at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

The given chemical equation follows:

CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

The expression of K_c for above equation follows:

K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

Putting values in above equation, we get:

K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of CO_2 needed be 'x' moles.

Now, equilibrium gets re-established:

              CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

Initial:       1.00      1.00              2.40       2.40

At eqllm:   (0.236+x)   0.236      3.164     3.164

Again, putting the values in the expression of K_c, we get:

5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13

Hence, the moles of CO_2 added to the system is 7.13 moles

You might be interested in
How many grams of hydrogen are in 46 g of CH40?<br>​
Romashka [77]

Answer:

5.8 grams of hydrogen

Explanation:

Your welcome

6 0
2 years ago
Read 2 more answers
A 4.86-gram sample of calcium reacted completely with oxygen to form 6.80 grams of calcium oxide. This reaction is represented b
sesenic [268]
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca

Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.

Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.

Hope this would help~
8 0
3 years ago
A researcher claims that an ancient scroll originated from greek scholars in about 500 bce. a measure of its carbon-14 decay rat
Naddik [55]
The amount of substance present in a certain object with a given half-life in terms of h can be expressed through the equation,

     A(t) = (A(o))(0.5)^(t/h)

where A(t) is the amount of substance after t years and A(o) is the original amount. In this item we are given that A(t)/A(o) is equal to 0.89. Substituting the known values,

     0.89 = (0.5)(t / 5730 years)

The value of t from the equation is 963.34 years.

<em>Answer: 963 years</em>
8 0
3 years ago
What is the relationship between the amount of substance ( concentration) and reaction rates?
jekas [21]

Answer:

Increasing the concentration of the reagents makes the collision between two molecules of the reagents more likely, thereby increasing the probability that the reaction will occur between these reagents.

As for the relationship between concentration and volume, density also comes into play, a higher volume, lower molarity and also lower concentration.

The pressure when increasing could generate a closer approach between the particles, therefore generating an increase in the reaction speed.

Pressure and volume are related but inversely proportional, therefore if the volume increases the pressure decreases and so on.

the reaction rate increases as the contact surface area increases. This is due to the fact that more solid particles are exposed and can be reached by reactant molecules.

A perfect reaction where the collision is promoted and the reaction speed advances is with the presence of a solvent, with an increase in pressure and a decrease in volume, with an increase in the exposure of the surface, with the presence of a catalyst, with increasing temperature and with increasing entrance

Explanation:

The reaction rate is defined as the amount of substance that is transformed into a certain reaction per unit of volume and time. For example, the oxidation of iron under atmospheric conditions is a slow reaction that can take many years but over time it is oxidized sooner or later by the oxygenation of its surface layer, but the combustion of butane in a fire is a reaction that happens in fractions of seconds, giving rise to an exothermic reaction with products such as CO2 and H2O

5 0
3 years ago
20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as
shepuryov [24]

The reaction forms 98.76 g AlCl_3.  

We have the masses of two reactants, so this is a <em>limiting reactant problem</em>.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1. Gather all the information</em> in one place with molar masses above the formulas and everything else below them.  

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the <em>limiting reactant</em>  

Calculate the moles of AlCl_3 we can obtain from each reactant.  

<em>From Al</em>: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

<em>From Cl_2</em>: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

<em>Cl_2 is the limiting reactant</em> because it gives the smaller amount of AlCl_3.

<em>Step 4</em>. Calculate the <em>mass of AlCl_3</em>.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0
2 years ago
Other questions:
  • What type of change produced the rust shown above? A. chemical, because a new substance with new properties was formed B. physic
    15·1 answer
  • Gas is trapped inside of a cell with volume 140 m3. The gas exerts 7600 Pa of pressure against the walls of the cell. A machine
    8·1 answer
  • Which of the following is a characteristic property of the noble gases?
    9·2 answers
  • Balance _Na+_H2O-&gt;_NaOH_H2
    11·2 answers
  • What is science? (1 point) Experimentation that discovers laws about the world around you. A body of knowledge and a process of
    8·1 answer
  • You are a meteorologist measuring the changing air pressure due to an approaching weather front. What instrument would you use t
    8·2 answers
  • What is the source of almost all energy on earth
    6·2 answers
  • WILL AWARD BRAINLIEST! I NEED HELP PLEASE! Match the states of matter for each of the five lines below.
    9·2 answers
  • Susie cooked sausages on a barbecue. Fat and water in the sausages changed state. which two changes of state occur during this p
    11·1 answer
  • Drag each label to the correct location. Each label can be used more than once.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!