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3 years ago

Find the volume of the sphere. Give the answer in terms of 3.14 and rounded to the nearest cubic foot

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

Sphere
Solve for volume
V=4
3πr3

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<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7

zhenek [66]

Answer:

Step-by-step explanation:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}$

$\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}$

$3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}$

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}$

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}$

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0

3 years ago

Factorize using identities:

ivann1987 [24]

Answer: i)169y^3z^3

ii) 225a^3b^3

iii) 145x^2y^2

Step-by-step explanation:

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3 years ago

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What is the height of a cylinder with a volume of 1,899.7 cubic inches and a radius of 11 inches?

FrozenT [24]

Not 100% sure.

Height = 37.81inches

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3 years ago

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Which expression and value represents 9 less than the quotient of 18 and 3?

olga55 [171]

Answer:

kinda hard ,

Step-by-step explanation:

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3 years ago

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what is the final amount of $3050.00 that is put into a savings account with 8% interest rate for 25 years, if the interest is c

Anna71 [15]

The formula required is:
$A=P(1+\frac{r}{n})^{nt}$
where A is the amount after t years of the principal P invested at an annual interest rate r (expressed as a decimal fraction) compounded n times per year.
Plugging in the given values, we get:
$A=3050(1+\frac{0.08}{4})^{(4\times25)}=22,096.17$
The final amount is $22,096.17

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