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Svetllana [295]
3 years ago
6

Help i need to ppooooppp

Mathematics
1 answer:
Daniel [21]3 years ago
5 0

Answer: b

Step-by-step explanation: There was the same question on brainly and they said that the submarine sandwich one was right.

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The area of a rectangle is 65 m2 , and the length of the rectangle is 3 m less than twice the width. find the dimensions of the
salantis [7]
X = <span>width
2x-3 = </span><span>length 

</span>x(2x-3) = 65\\&#10;2x^2 - 3x - 65 = 0 \\ D=b^2-4ac=(-3)^2-4*2*(-65)=529\\&#10;x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{3б 23}{4} \\ x_1=-5  \ \ \O \\ x_2=6.5 \ \

width = 6.5 m
length  = 2x-3 = 2*6.5 - 3 = 10 m
4 0
3 years ago
How much flour does Carlos use?
Nostrana [21]
HEY THERE.

THE CORRECT ANSWER IS....... CARLOS USES 0.75
4 0
3 years ago
What is the simplest form for the fractions 12/30,12/20 and 21/35
Yuki888 [10]
Simplest form of:
12/30=2/5
12/20=3/5
21/35=3/5
6 0
3 years ago
Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
2 years ago
How many solutions does the system have?
sertanlavr [38]
If a solution(s) exists y=y so we can say:

x^2-3x=-2x+2  add 2x to both sides

x^2-x=2  subtract 2 from both sides

x^2-x-2=0  factor

(x-2)(x+1)=0

So x=-1 and 2, using y=-2x+2 we find:

y(-1)=4 and y(2)=-2

So the two solutions occur at the points:

(-1,4) and (2,-2)
4 0
3 years ago
Read 2 more answers
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