D = π(bore / 2)² · stroke · n
can be rewritten as
D = π(1/2 * bore)² · stroke · n
If bore = k /2, and stroke = h, and # of cylinders = n = 8, then
D = π(1/2 * k/2)² · h · 8
= 8π*h(k/4)²
= 8π*h(k²/16) since (k/4)² = k²/4² = k²/16
= π*h*k²/2
Answer for the first part: D = π*h*k²/2
For second part, if bore = 4 inches, stroke is 3.4 inches, and # cylinders = n = 4, then
D = π(1/2 * bore)² · stroke · n
D = π(1/2 * 4)² · 3.4 · 4
D = 170.9 cubic inches
Answer:
1. Pattern (rule) : y = x-6
2. Pattern (rule) : y=x^2+1
3. Pattern (rule) : y = -3x
4. Pattern (rule) : y = 2x-2
5. Pattern (rule) : y = x^2
Step-by-step explanation:
Note: question number correspond to your order of questions.
1. Pattern (rule) : y = x-6
for missing parts, see attached table.
2. Pattern (rule) : y=x^2+1
3. Pattern (rule) : y = -3x
4. Pattern (rule) : y = 2x-2
5. Pattern (rule) : y = x^2
Answer:
The calculated 99% confidence interval is wider than the 95% confidence interval.
Step-by-step explanation:
We are given the following in the question:
95% confidence interval for the population proportion
(0.65, 0.69)
Let
be the sample proportion
Confidence interval:


Let x be the standard error, then, we can write

Solving the two equations, we get,

99% Confidence interval:


Putting values, we get,

Thus, the calculated 99% confidence interval is wider than the 95% confidence interval .
The greatest common factor would be 8
Answer:
D. -3
Step-by-step explanation:
Add all numbers together = -15
then divide by the numbers of numbers = 5
= -3