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blagie [28]
2 years ago
14

2+square root x+4:10

Mathematics
1 answer:
Katyanochek1 [597]2 years ago
6 0

Assuming the ':' means an = sign, 2\sqrt{x+4}=10 simplifies to 2\sqrt{x}=8

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Given the image, solve for the problem.
quester [9]

Answer:1.5 hours

Step-by-step explanation:

$8.50 is for 1/2 hour

In $25.50, the can use for (25.5*.5)/8.5 = 1.5 hours

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What is an equation of the line that passes through the point (-2 1) and is parallel to the line whose equation is 4x-2y=8 ?
monitta
4x-2y=8 ==> y=2x-4 (to better show you what I mean) 

2 lines are parallel if they have the same slope (m the coefficient of x).

So y=mx + b // y =2x-4 means m=2 & y=mx + b, becomes y=2x + b.
Moreover they are telling us that this function passes by (-2,1), where -2 represents x & 1, represents y. To calculate b , replace x & y by their values:
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3 years ago
15% of people on the beach do not wear sun screen. If 30 people don't wear sunscreen, what is the total number of people at the
lara [203]

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6 0
3 years ago
Two numbers that multiply to -100 and add to 15
Whitepunk [10]

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3 0
3 years ago
Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
1 year ago
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