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statuscvo [17]
3 years ago
8

Ava is raising money for a school trip by selling bags of chips and candy bars. The price of each bag of chips is $1.75 and the

price of each candy bar is $1. Yesterday Ava made $26 from selling a total of 17 bags of chips and candy bars. If b = 12 and c = 5, what do the answers mean in the context of the problem?
Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0
Make a formula using info given. 1.75chips+1candy=$26; so to make this true. b=chips and c=candy
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Naoya read a book cover to cover in a single session, at a rate of 555555 pages per hour. After 444 hours, he had 350350350 page
natali 33 [55]

Answer:

y=-55x+570

Step-by-step explanation:

The correct question is

Naoya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had 350 pages left to read.

Let y represent the number of pages left to read after x hours.

Complete the equation for the relationship between the number of pages left and number of hours.

Let

x -----> the time in hours

y ----> the number of pages left to read

we know that

The linear equation in point-slope  form is equal to

y-y1=m(x-x1)

In this problem we have

m=-55\frac{pages}{hour}  ----> is negative because the linear function is decreasing

point\ (4,350)

substitute

y-350=-55(x-4)

y-350=-55x+220

y=-55x+220+350

y=-55x+570

8 0
4 years ago
A regular polygon has an odd number of sides. Which statement is true about the lines of reflection for the polygon that will ma
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3 years ago
There are two bags of marbles. Bag A contains 9 red marbles and 3 green marbles. Bag B contains 9 black marbles and 6 orange mar
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3 0
4 years ago
Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble
Ksivusya [100]

Answer:

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

So, total marbles in the bag = 6 + 4 = 10 marbles

Now,if E : Any given event, then

\textrm{P (Event E)} = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total Outcomes}}

So, here \textrm{P (Picking a Red marble)} = \frac{\textrm{Total number of red marble}}{\textrm{Total marble}} = \frac{6}{10}  = \frac{3}{5}

⇒ P(a Red ball)  = 3/5    ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag  = 10

So, here \textrm{P (a Blue marble)} = \frac{\textrm{Total number of blue marble}}{\textrm{Total marble}} = \frac{4}{10}  = \frac{2}{5}

⇒ P(a Blue marble)  = 2/5    ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble)  = 3/5 x 2/5  = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

7 0
3 years ago
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