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IrinaK [193]
3 years ago
6

Did panagea occur or is it a myth

Mathematics
2 answers:
zysi [14]3 years ago
7 0
I think it occured
bc we talked about this in my class not to long ago

Alexus [3.1K]3 years ago
4 0
Yes it did occur it was just a very long time ago. As the earth grew and developed the countries separated and that is why they are spread all over the world now. Hope this helps.
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Graph each figure with the given vertices and its image after the indicated glide reflection. : R(1, -4), S(6, -4), T(5, -1) Tra
Yuki888 [10]

Answer:

Step-by-step explanation:

7 0
3 years ago
Which is the graph of y=3/4x-3<br><br> Graph A<br> Graph B<br> Graph C.
irina [24]

Answer:

Graph A

Step-by-step explanation:

I had this question in my class and got it right with answer A :')

8 0
3 years ago
One root of f(x) = x + 10x2 – 25x – 250 is x = -10. What are all the roots of the function? Use the Remainder Theorem.
Natalka [10]

Answer:

-10

-5

5

Step-by-step explanation:

From the answers given, you probably mean f(x) = x^3 + 10x2 – 25x – 250

The Remainder Theorem is going to take a bit to solve.

You have to try the factors of 250. One way to make your life a lot easier is to graph the equation. That will give you the roots.

The graph appears below. Since the y intercept is -250 the graph goes down quite a bit and if you show the y intercept then it will not be easy to see the roots.

However just to get the roots, the graph shows that

x = -10

x = - 5

x = 5

The last answer is the right one. To use the remainder theorem, you could show none of the answers will give 0s except the last one. For example, the second one will give

f((10) = 10^3 + 10*10^2 - 25*10 - 250

f(10) = 1000 + 1000 - 250 - 250

f(10) = 2000 - 500

f(10) = 1500 which is  not 0.

==================

f(1) = (1)^3 + 10*(1)^2 - 25(1) - 250

f(1) = 1 + 10 - 25 - 250

f(1) = -264 which again is not zero

3 0
3 years ago
Read 2 more answers
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
2 years ago
Read 2 more answers
Which statement is true about this data set?<br> 3,1, 6, 4, 4, 4, 3, 2, 5, 3
Kobotan [32]

Answer:

What statements?

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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