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masya89 [10]
3 years ago
5

Ice sheet movement rates have varied from about 50 to 320 meters per year for the margins of the ice sheet advancing from the Hu

dson Bay region during the Ice Age. If an ice sheet moved from the southern end of Hudson Bay to the south shore of present-day Lake Erie, a distance of 1,600 kilometers, what would the maximum amount of time required to be?
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

32000 years

Step-by-step explanation:

Movement rate range from 50 to 320m per year.

The fastest is 50m/yr

The slowest is 320m/yr

The range of time must be between the time of the slowest to the fastest.

Obviously, the longest time (maximum) taken would be the slowest value

Using the formula of speed

Speed = distance/time

Time = distance/speed

We have to convert distance in km to m since the speed is in meter per year.

Distance = 1600 km = 1,600,000m

Therefore, maximum time is

t = 160000 / 50 = 32000 years.

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Solve the following system : -x + 5y = 8 and 3x + 7y = -2
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-x + 5y = 8

multiply this equation by 3

-3x + 15y = 24

now add it to the other equation  ( elimination)

-3x + 15y = 24

3x + 7y = -2

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0x  + 22 y = 22

divide each side by 22

y =1


substitute into -x + 5y =8  to find x

-x + 5(1) = 8

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divide by -1

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Answer (-3,1)

Choice A


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3 years ago
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

sin(A -B) = sin(A)cos(B) -sin(B)cos(A)

We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

Then ...

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3 0
3 years ago
15 + 10y - 4xy - 6 6.​
Verdich [7]

Answer:

Step-by-step explanation:

15+10y−4xy−66

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−51+10y−4xy

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3 years ago
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