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masya89 [10]
3 years ago
5

Ice sheet movement rates have varied from about 50 to 320 meters per year for the margins of the ice sheet advancing from the Hu

dson Bay region during the Ice Age. If an ice sheet moved from the southern end of Hudson Bay to the south shore of present-day Lake Erie, a distance of 1,600 kilometers, what would the maximum amount of time required to be?
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

32000 years

Step-by-step explanation:

Movement rate range from 50 to 320m per year.

The fastest is 50m/yr

The slowest is 320m/yr

The range of time must be between the time of the slowest to the fastest.

Obviously, the longest time (maximum) taken would be the slowest value

Using the formula of speed

Speed = distance/time

Time = distance/speed

We have to convert distance in km to m since the speed is in meter per year.

Distance = 1600 km = 1,600,000m

Therefore, maximum time is

t = 160000 / 50 = 32000 years.

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Answer:

r = 1/6

Step-by-step explanation:

\dfrac{3}{4}r=\dfrac{1}{8}\\\\\\

Multiply both sides by 4

4*\dfrac{3}{4}r=4*\dfrac{1}{8}\\\\3r = \dfrac{1}{2}

Divide both sides by 3

\dfrac{3}{3}r=\dfrac{1}{2*3}\\\\r = \dfrac{1}{6}

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Samples of a cast aluminum part are classified on the basis of surface finish (in microinches) and edge finish. The results of 1
liubo4ka [24]

Answer:

a) P (A)= 88/102= 0.8627

(b) P (B)=  89/102= 0.8725

c) P (A`) =  14/102 = 0.1372

(d) P (A∩B) = 84/102 =0.8235

(e) P(AUB)= 93/102 = 0.9117

(f)P (A`UB) = 98/102= 0.96078

Step-by-step explanation:

                                                                   edge                  

                                                  finish excellent       good           Total

<u>(A )surface finish excellent            84                      4                  88</u>

good                                    ( B) ⇵    5                       9                  14

Total                                               89                      13                102

a) Upper P left-parenthesis Upper A right-parenthesis equals

P (A)= 88/102= 0.8627

All the elements of set A = 84+4= 88

(b) Upper P left-parenthesis Upper B right-parenthesis equals

P (B)=  89/102= 0.8725

All the elements of set B = 84+5= 89

c) Upper P left-parenthesis Upper A prime right-parenthesis equal

P (A`) =  14/102 = 0.1372

All the elements of Universal set U which are not elements of set A = 102- 88= 14

(d) Upper P left-parenthesis Upper A intersection Upper B right-parenthesis equals

P (A∩B) = 84/102 =0.8235

Only those elements of set A and set B which are common

(e) Upper P left-parenthesis Upper A union Upper B right-parenthesis equals

P(AUB)= 93/102 = 0.9117

Totalling elements of set A and B= 88+5= 93

(f) Upper P left-parenthesis Upper A prime union Upper B right-parenthesis equals

P (A`UB) = 98/102= 0.96078

All the elements of Universal set U which are not elements of set A and the elements of Set B = 5+9+ 84= 98

6 0
3 years ago
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