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3 years ago

Resolva os sistemas abaixo 2x+3y=80 3x+2y=70 X=8y X+4y=480

1 answer:

7 0

Solución 1: 2(x) + 3(y) = 80
solución 2: 3(x) + 2(y) = 70

3(y) + 2(x) = 80
2(y) + 3(x) = 70

2y = -3x + 70
y = -3x÷2 + 35

2x + 3(-3x÷ 2+35) = 80
-5x÷2 = -25
-5x = -50

5x = 50
x-intercept: 10
x = 10
y = -3x÷ 2+35

y = -(3÷2)(10)+35 = 20

x-interpcet: 10
y-intercept: 20
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
solución: x - 8y = 0
solución x + 4y = 480

-8y + x = 0
4y + x = 480

x-intercept (solución 2)
x = -4x + 480

x-intercept (solución 1)
4y + 180 - 8y = 0
-12y = 480

y-intercept: 40
x-intercept: 320

Buena Suerte!

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The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

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