Answer:
Option C. No solution is the right answer.
Step-by-step explanation:
Here the given equations are y = x²+2x+3 -----(1)
and y = 4x-2 -------(2)
Now we substitute the value of y from equation 2 into 1.
x²+2x+3 = 4x-2
x²+2x+3-2x = 4x-2-2x
x²+3 = 2x-2
x²+3-2x = 2x-2x-2
x²-2x+3 = -2
x²-2x+5 = 0
Then value of
Since in this solution √(-20) is not defined. Therefore there is no solution.
Answer
B)
Step by step explanation
The standard form of circle when center(h, k) and radius r, given is
(x - h)^2 + (y - k)^2 = r^2
Given: (h, k) = (5, 0) and r = 3
Now plug in these values in the standard form, we get
(x - 5)^2 + (y - 0)^2 = 3^2
Therefore, the answer is B)
Thank you :)
Answer:
C.
Step-by-step explanation:
I think the equation meant ?
Anyways, to factor these kinds of quadratic, keep into consideration:
ONLY if:
Start off by finding factors of c, which in this case, -18:
±(1, 2, 3, 6, 9, 18)
If one of the numbers is negative then the other number must be positive.
Find which two factors will sum up to b, which in this case, is 3.
The only two factors that work are 6 and -3.
Replace them into the factored form:
