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3 years ago

Randy filled 48 pint jars to the top with jelly. How many gallons of jelly did Randy make it? Explain.

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

Step-by-step explanation:

The conversion is half (1/2) Every 1 quart is two pints. If Randy had 48 pints of jelly, we simply divide 48 by 2...

$48/2=24$

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The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is twice the

Mashcka [7]

X=45, X=62
X=73 thank me i am your savior I gave you the answer say thank you now you know

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1 year ago

If f(x) = 7x+6 and g(x)=8x-4 find f(g(-2))

sp2606 [1]

Answer:

$f(g(-2))=-134$

Step-by-step explanation:

So we have the two functions:

$f(x)=7x+6\text{ and } g(x)=8x-4$

And we want to find f(g(-2)).

First, let's find g(-2):

$g(-2)=8(-2)-4$

Multiply:

$g(-2)=-16-4$

Subtract:

$g(-2)=-20$

Now, substitute:

$f(g(-2))=f(-20)$

Now, find the value of f(-20):

$f(-20)=7(-20)+6$

Multiply:

$f(-20)=-140+6$

Add:

$f(-20)=-134$

So:

$f(g(-2))=-134$

And we're done!

5 0

3 years ago

Determine which expression has the greatest value.

fgiga [73]

Well D I would think because 52 is greater than the other number :)
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8 0

2 years ago

Read 2 more answers

A) The ratio 20 minutes to 1 hour can be written in the form 1:n. Find the value of n. n =

Serhud [2]

Answer:

n =3

Step-by-step explanation:

20 minutes to 1 hour can also be written as 20 minutes to 60 minutes.

when simplified, you get 1:3

5 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

2 years ago