The picture in the attached figure
we know that
area of rectangle=base*height
in this problem
base is 22 ft
height is 2 yd
convert yd to ft
1 yd is equal to 3 ft
2 yd--------> 2*3-----> 6 ft
area of rectangle=22*6-----> 132 ft²
the answer is132 ft²
The product (multiplication) of 5 and m squared (²) increased (addition) by the sum (addition) of the square (²) of m and 5.
(5m²) + (m² + 5)
Answer:
There's no equation. You must've forgotten to put the file in the question.
4c + 5h = 650 and
5c + 6h = 800 where c are chefs, h are helpers
Start by finding an expression for c
4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4
Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50
Take that 50 and substitute it into the expression we have for c to get a number value for c
C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100
Check your first equations, substituting $50 for the helpers and $100 for the chefs.
4 (100) + 5(50) =
400 + 250 = 650
5(100) + 6(50) =
500 + 300 = 800
Answer:
Is this for a Trig class? just wondering
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
we want to find the Hypotenuse (Hyp) and are given an angle and the adjacent side (adj) sooo use CAH , b/c it has all of the pieces
Cos(37) = Adj / Hyp
Cos(37) = 11 / Hyp
swap Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra
Hyp = 11 / Cos(37)
now solve with your handy TI 83 / 84 / 89 calculator :) if you don't have one go get one . :D get the 89 if you are going into engineering classes... the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )
Hyp = 13.77349...
Hyp = 13.8 ( rounded to nearest 10th ) :)
