Answer:
D)4x + 6/(x + 1)(x - 1)
Step-by-step explanation:
A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle
where
is the perimeter
is the length
is the width
We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so 
and 
.
Replacing values:
Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula 
where 
is the first term and 
is the second term. We can infer that 
and 
. So, 
. Replacing that:
We can see that the common denominator of our fractions is 
. Now we can simplify our fraction using the common denominator:
We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).
Answer:
Quadrant 4
Step-by-step explanation:
Answer:
Solution : Option C
Step-by-step explanation:
We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations ( x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.
Given : x = - 9,
( Substitute r cos(θ) for x )
r cos(θ) = - 9,
r = - 9 / cos(θ)
( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )
r = - 9 sec(θ)
Therefore the third option is the correct solution.
