We have to know the product formed on reaction of ethyl iodide with triethylamine.
The product is tetraethylammonium iodide salt.
On reaction of ethyl iodide with triethylamine, a quarternary salt is produced which is ionic in nature. The salt is ionic and polar, it gets dissolved in polar solvent but insoluble in non-polar solvent.
As it is ionic compound, its melting point is high, it does not melt below 200°C.
The structure of the product (tetraethylammonium iodide salt) is shown below:
Sulfur dioxide(SO2)
Diphosphorus Pentachloride(P2Cl5)
Dinitrogen tetroxide(N204)
You can use the formula triangle . You can find it on google.
Answer:
alkali metals: 1 valence electron, very reactive metals
alkaline earth metals: 2 valence electrons, reactive metals
halogens: 7 valence electrons, very reactive nonmetals
noble gases: 8 valence electrons, very little reactivity
Explanation:
The groups increase by 1 valence electron as you move from left to right across the periodic table, skipping over the transition metals. The closer an element is to having a full octet of 8 valence electrons, the more reactive it will be. The alkali metals and halogens are both just 1 away from an octet -- alkali lose an electron, halogens gain one. This makes them very reactive.