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3 years ago

Name these covalent compounds: SO2, P2Cl5, and N2O4

2 answers:

8 0

Sulfur dioxide-----(SO2)

Diphosphorus Pentachloride------(P2C15)

Dinitrogen tetroxide------(N2O4)

Hope this helps!

~Hottwizzlers

Pie3 years ago

6 0

Sulfur dioxide(SO2)
Diphosphorus Pentachloride(P2Cl5)
Dinitrogen tetroxide(N204)

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The main buffering agents in human blood are h2co3 and hco3. Explain how this buffering system will be able to maintain blood pH

den301095 [7]

Answer:

The base, HCO₃⁻ of the buffering system will neutralize the acid added forming H₂CO₃.

Explanation:

A buffer solution keeps the pH in a narrow range upon the addition of an acid or base. A buffer consists of a pair of a weak acid and its conjugate base, or vice versa, in a pair of a weak base and its conjugate acid. In the case of human blood, the acid is H₂CO₃ and its conjugate base is HCO₃⁻.

The buffering system of the human blood maintain blood pH at a steady level when a small amount of a generic acid HA is added in the following way:

HCO₃⁻ + HA ⇄ H₂CO₃ + A⁻

The base, HCO₃⁻, will neutralize the acid added forming the H₂CO₃, which is already a component of the buffering system of the human blood. Thus, hydronium ions of the acid added are removed, preventing the pH of blood from becoming acidic.

On the other hand, when a small amount of a generic base A⁻ is added the following reaction takes place:

H₂CO₃ + A⁻ ⇄ HCO₃⁻ + HA

In this case, the acid H₂CO₃ will neutralize the base added to form the base HCO₃⁻, which is already a component of the buffering system. Thus, the base added are removed from the blood, preventing the pH of blood from becoming basic.

Since, the acid or its conjugate base will react with the base or acid added, to neutralizing it and forming the species that conform the buffer solution, the pH is being maintained at a steady level.

In the process above, the addition of a small amount of an acid or a base won't change in a significant way the concentrations of the two components of the buffering system. This buffering mechanism prevents the blood from becoming acidic or basic.

I hope it helps you!

6 0

3 years ago

Which of the following statements accurately describes enzymes?

aniked [119]

The answer is a. temperature and pH can affect how the enzymes work

5 0

3 years ago

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i

IRINA_888 [86]

Answer : The pressure after the temperature change is, 0.752 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure = 0.82 atm

$P_2$ = final pressure = ?

$T_1$ = initial temperature = $21^oC=273+21=294K$

$T_2$ = final temperature = $-3.5^oC=273+(-3.5)=269.5K$

Now put all the given values in the above equation, we get:

$\frac{0.82atm}{294K}=\frac{P_2}{269.5K}$

$P_2=0.752atm$

Thus, the pressure after the temperature change is, 0.752 atm

4 0

4 years ago

If gas is initially at 350L and 500k then changes to 295K what is the new volume

Dimas [21]

<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

We are given:

$V_1=350L\\T_1=500K\\T_2=295K$

Then, using the Charle's Law equation, we have:

$\frac{350L}{500K}=\frac{V_2}{295K}$

$\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L$

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

5 0

3 years ago

Enter the atomic symbol, including mass number and atomic number, for iodine-125.

ICE Princess25 [194]

Answer:

Explanation:

Iodine - 125

The atomic symbol of iodine is ¹²⁵₅₃ I

The symbol for iodine is I

The atomic number of iodine is 53,

and the atomic mass of iodine is 125 .

<u>The representation of the atomic symbol is as, the atomic mass is written in uppercase and the atomic number is written in lower case , followed by the symbol of the element .</u>

Iodine is a radio active element , used for many biological process .

It is the second largest -lived radioisotope of iodine .

The first is iodine-129 .

3 0

3 years ago