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Naya [18.7K]
3 years ago
12

What is the numerical value of the rate constant for a reaction in which [A] is reduced from 0.380 M to 0.215 M in a span of 26.

3 s? Assume the units of the rate constant are s-1. Please enter your response to three of significant figures using E notation. For example, to report 1347.54 to three significant figures, type: 1.35E3
Chemistry
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

k = 2.17E-2 s-1

Explanation:

Initial Concentration [A]o = 0.380 M

Final Concentration [A] = 0.215 M

time, t = 26.3 s

Unit of rate constant =  s-1

Rate constant = ?

The units of the rate constant depends on the order of the reaction. This is a first order reaction due to the units.

The integral rate law for a first order reaction is;

ln[A] = ln[A]o - kt

ln(0.215) = ln(0.380) - k(26.3)

ln(0.215) - ln(0.380) = - k(26.3)

- k(26.3) = -0.57

k = 0.57 / 26.3 = 0.02167

Reporting to three significant figures using E notation;

k = 2.17E-2 s-1

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In the following reaction, identify the oxidized species, reduced species, oxidizing agent, and reducing agent. Be sure to answe
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Answer :

Cl_2 is reduced species.

KI is oxidized species.

Cl_2 is oxidizing agent.

KI is reducing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

Cl_2(aq)+2KI(aq)\rightarrow 2KCl(aq)+I_2(aq)

The half oxidation-reduction reactions are:

Oxidation reaction : 2I^-\rightarrow I_2+2e^-

Reduction reaction : Cl_2^++2e^-\rightarrow 2Cl^-

From this we conclude that the 'KI' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'Cl_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, Cl_2 is reduced species.

KI is oxidized species.

Cl_2 is oxidizing agent.

KI is reducing agent.

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