Answer:
The valence electrons of nitrogen in its compounds are all sp³ hybridized orbitals. The formal charge on N is usually -1 for an anion, 0 for a neutral compound, and +1 in cations. A nitrogen atom with a formal charge of -3 would correspond to a nitride ion, N³⁻, which is strongly basic in aqueous solution. Hope this helps...
Explanation:
Brainliest please?
Answer:
Explanation:
Before writing this equation in a molecular equation form, let's identify each species:
- phosphorus is a non-metal represented by 'P', it is solid at standard conditions;
- iron(III) oxide is an ionic compound consisting of iron(III) cations with a 3+ charge, as well as of oxide anions with a 2- charge, this means we may represent it as , which is also a solid material at standard conditions;
- tetraphosphorus decoxide consists of 4 phosphorus atoms and 10 oxygen atoms, as stated by the prefixes, this is also a solid;
- iron metal is simply 'Fe'.
Putting all of this into a single equation and balancing it, we obtain:
<u>Answer:</u> The density of sugar is
<u>Explanation:</u>
To calculate the density of a substance, we use the equation:
We are given:
Mass of sugar = 316 g
Volume of box =
Putting values in above equation, we get:
Hence, the density of sugar is
Balancing means there are equal amount of molecules on each side, both reactant and products. This is a method I like to do.
Under, I count how many molecules are in each side.
Cr2O3+Mg -->Cr + MgO
Cr: 2 1
O: 3 1
Mg: 1 1
Let's guess and make the number of oxygens equal on both sides.
Cr2O3+Mg -->Cr + 3MgO
Cr: 2 1
O: 3 3 EQUAL
Mg: 1 3
See what we did there? We multiplied the MgO on the products side by 3 so we can have 3 oxygens. Now let's multiply the Mg on the reactants by three so Mg AND O can be equal.
Cr2O3+3Mg -->Cr + 3 MgO
Cr: 2 1
O: 3 3 EQUAL
Mg: 3 3 EQUAL
Finally, we just need to multiply the loner Cr in the products side by two to make it equal for all elements.
Cr2O3+3Mg -->2Cr + 3 MgO