All categories

2 years ago

Answer the question below !

Mathematics

1 answer:

cupoosta [38]2 years ago

3 0

Answer:

63 yrd cubed

Step-by-step explanation:

7x9x3=189

1/3 x 189= 63

You might be interested in

A vcr and tv were bought for 8000 each. The shopkeeper made a loss of 4 per cent on vcr and 8 per cent prophit on the tv. Find t

aleksley [76]

Answer:

2% gain

Step-by-step explanation:

We assume the shopkeeper bought the appliances at the indicated prices, and that gain is computed on the basis of that cost price.

Since the base cost is the same for each appliance, the percentages can be added directly to find the percentage gain on 8000. However, the shopkeeper's total outlay was 16000, not 8000, so the final gain percentage is half of that total.

gain percent = (-4% + 8%)/2 = 2%

_____

If you want to see the actual numbers:

Loss on VCR = 4% × 8000 = 320.

Gain on TV = 8% × 8000 = 640.

Total gain on 16000 is -320 +640 = 320. As a percentage, that is ...

320/16000 × 100% = 2%

7 0

3 years ago

The number −5 is all of the following except _____.

nirvana33 [79]

Answer:

a real number

Step-by-step explanation: You didn't list the choices- a real number is all positive numbers except 0

7 0

2 years ago

ILL MARK BRAINLIST

Mkey [24]

Answer:

vertical angles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

One number is 5 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 331,

Yuri [45]

Answer:

33, 165, 133

Step-by-step explanation:

Check this file for the solution!

Download pdf

3 0

1 year ago

Read 2 more answers