Answer: y= -1x - 5
Step-by-step explanation:
The equation has to be in slope-intercept form which uses the formula
y=mx+b where m is the slope and b is the y-intercept.
So we given the slope and an x and y coordinate so we will plot those numbers into the formula and solve for the y intercept to write the equation.
the x coordinate is -7 and the y coordinate is 2
2 = -1(-7) + b
2 = 7 + b
-7 -7
b = -5 the y intercept is -5
Now the equation will be y= -1x - 5
Answer: ![\sqrt[5]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%7D)
I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"
The rule I'm using is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
and the more general rule we could use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.
First, lets break up the equation into pieces.
The first variable is slope, in your case here, we have a slope of -3 or -3/1.
The other variable is the y-intercept, which is where place on the graph where you plot (0,X), in your case here we got (0,-4). That is the y-intercept.
to graph it you have to plot the y-intercept, and then identify the slope.
Here is an example.
Answer:
60
Step-by-step explanation:
product means multiplication
therefore 6×10=60
Answer:
the linear function gives us the points
(0,3)
(4,0)
(8,-3)
find the equation
hm
find slope
(y2-y1)/(x2-x1)
for (0,3) and (4,0)
slope=(0-3)/(4-0)=-3/4
y=-3/4x+b
given
(0,3)
y=-3/4x+3
so sub -3/4x+3 for y in other equation
(-3/4x+3)^2+x^2=4
expand
9/2x^2-9/2x+9+x^2=4
11/2x^2-9/2x+9=4
times 2 both sides
11x^2-9x+18=8
minus 8 both sides
11x^2-9x+10=0
factor
or use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
2a
−b+/−
b
2
−4ac
11x^2-9x+10=0
x=\frac{-(-9)+/- \sqrt{(-9)^2-4(11)(10)} }{2(11)}
2(11)
−(−9)+/−
(−9)
2
−4(11)(10)
x=\frac{9+/- \sqrt{81-440} }{22}
22
9+/−
81−440
x=\frac{9+/- \sqrt{-359} }{22}
22
9+/−
−359
we see we have no real roots
there are no intersection points
#Carry on learning
#Correct me if I'm wrong
