-14x + 5 = 34
-14x = 29
x = -2.10
Answer:
value of x = 2.8
Step-by-step explanation:
By law of cosines,

Given:
The equation of a line is:

The line is dilated by factor 3.
To find:
The result of dilation.
Solution:
The equation of a line is:

For
,




For
,




Divide both sides by 2.


The given line passes through the two points A(0,5) and B(2,2).
If the line dilated by factor 3 with origin as center of dilation, then

Using this rule, we get


Similarly,


The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:




Multiply both sides by 2.



Therefore, the equation of the line after the dilation is
.