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4 years ago

If P(A) = 0.996, what is the value of P(A)?

Mathematics

1 answer:

andrew11 [14]4 years ago

4 0

Answer:

$p(a) = 0$

Step-by-step explanation:

$p(a) = 0.966$

Find the derivative of the fraction

$p(a) = \frac{d}{da} ( 0.966)$

Convert the decimal number to a fraction

$p(a) = \frac{d}{da} ( \frac{249}{250} )$

The derivative of a constant is always 0

$p(a) = 0$

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Find the P-value for the hypothesis test with a standardized test statistic z. Decide whether toreject the null hypothesis for t

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1.) We don't reject the null

2.) We reject the Null

3.) We do not reject the null

Step-by-step explanation:

Obtaining p values using test statistic:

Given that ; we have a standardized test statistic and α - values ;

Let's define the decision region :

If Pvalue < α ; Reject H0 ; otherwise, fail to reject H0

A.)

Left tail , Z = - 1.32 ; α = 0.10

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Pvalue = 0.934

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B.)

Right-tailed test, z = 2.46, α = 0.01

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Two-tailed test, z = -1.68, α = 0.05

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3 years ago

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3 years ago

Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,

scoundrel [369]

Answer: $\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

$23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes$

You know that he had 30 minutes in time-out, he counted spots on the ceiling for $\frac{70}{3}$ minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and $\frac{70}{3}$ minutes:

$30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

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3 years ago

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