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tino4ka555 [31]
3 years ago
13

Han wants to buy a $30 ticket to a game, but the pre-order tickets are sold out. He knows there will be more tickets sold the da

y of the game, with a markup of 200%. How much should Han expect to pay for the ticket if he buys it the day Of the game?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:$90


Step-by-step explanation: $30 is the cost. 200 is the percent of Mark-up, so you take 100 percent of 30 and add it together then you get 60. Repeat that step for a total of 90. 100 percent of 30 is 30. So 30+ 30+ 30 = 90.


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Harrizon [31]
Equation 2:
3(18 - 3) = 45
step 1 do 18-3
now you have
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and it’s just three, times fifteen.
3 • 15 = 45

Equation 1:
3x + 11 = 11
3x = 11 - 11
3x = 0 (divide both sides by 3 to get x)
3x/3 = 0/3
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3 0
3 years ago
Please I’m giving away Brainly ASAP
AnnyKZ [126]

Answer:

g and f are inverse functions because g(f(x)) = f(g(x)) = x

Step-by-step explanation:

Let's start by finding f(g(x)) and g(f(x)). As we discussed in another question, to find a composite function, apply the outer function to whatever the inner function evaluates to. We can start with f(g(x)):

f(g(x))=f(\frac{x+6}{7})=7(\frac{x+6}{7} )-6=x+6-6=x

Now, let's find g(f(x)):

g(f(x))=g(7x-6)=\frac{(7x-6)+6}{7} =\frac{7x}{7}=x

There is a property that says that if f(g(x)) = g(f(x)) = x, the two functions are inverse. This suggests that g and f are inverse functions. We can verify this by taking one function, switching y and x, and then solving for y. If we complete this process and find that we get the OTHER function, it means the two functions are inverse. Let's try that:

f(x)=y=7x-6

Swap x and y:

x=7y-6

Solve for y:

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7 0
2 years ago
A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per gallon is add
RUDIKE [14]

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The net rate of change of the amount of salt in the tank at time t is then governed by

\dfrac{\mathrm dQ}{\mathrm dt}=3-6Q

Solve for Q:

\dfrac{\mathrm dQ}{\mathrm dt}+6Q=3

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\dfrac{\mathrm d}{\mathrm dt}[e^{6t}Q]=3e^{6t}

e^{6t}Q=\dfrac{e^{6t}}2+C

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10=\dfrac12+C\implies C=\dfrac{19}2

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\boxed{Q(t)=\dfrac{1+19e^{-6t}}2}

4 0
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yanalaym [24]
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8 0
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JulsSmile [24]

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8 0
3 years ago
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