steps
(x) = 5x^2-3x+7
refine
x=5x^2-3x+7
Switch sides
5x^2-3x+7-x=x-x
Subtract x from both sides
5x^2-4x+7=0
Solve with the quadratic formula
Answer:
the answer is B
Step-by-step explanation:
Answer:
Step-by-step explanation:
Combine real terms and combine complex terms
1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i
= 5 + (2-5)i
= 5 + (-3)i
= 5 - 3i
3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i) = 2 -1 + 2i + 4 - 5i - 1 + 3i
{- is distributed to (1 - 2i) & - is distributed to (1- 3i)}
= 2 - 1 + 4 + 1 + 2i - 5i + 3i
= 6 +0i = 6
5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i
= 8
7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i {(a - b)² = a² - 2ab +b²}
= 9 -12i + 4i² + 3 + 2i
= 9 - 12i + 4*(-1) + 3 + 2i {i² = -1}
= 9 +3 - 4 - 12i +2i
= 8 - 10i

<u>ANSWER</u>

<u>EXPLANATION</u>
The given function is

We make the coefficient of
unity by factoring
out of the last two terms to obtain;

We now add and subtract half the coefficient of
multiplied by a factor of 6 to obtain;

We now factor 6 out of the last two terms to get;


The quadratic trinomial in the parenthesis is now a perfect square.

Hence the vertex form of the polynomial is

R=3
Vcyl.=36(9π)=324π
Vcone=4(9π)=36π
V pencil=324π+36π=360π