The sum of the first four terms of the sequence is 22.
In this question,
The formula of sum of linear sequence is

The sum of the first ten terms of a linear sequence is 145
⇒ 
⇒ 145 = 5 (2a+9d)
⇒ 
⇒ 29 = 2a + 9d ------- (1)
The sum of the next ten term is 445, so the sum of first twenty terms is
⇒ 145 + 445
⇒ 
⇒ 590 = 10 (2a + 19d)
⇒ 
⇒ 59 = 2a + 19d -------- (2)
Now subtract (2) from (1),
⇒ 30 = 10d
⇒ d = 
⇒ d = 3
Substitute d in (1), we get
⇒ 29 = 2a + 9(3)
⇒ 29 = 2a + 27
⇒ 29 - 27 = 2a
⇒ 2 = 2a
⇒ a = 
⇒ a = 1
Thus, sum of first four terms is
⇒ 
⇒ 
⇒ S₄ = 2(2+9)
⇒ S₄ = 2(11)
⇒ S₄ = 22.
Hence we can conclude that the sum of the first four terms of the sequence is 22.
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Answer:/?idk
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
Just respond if you have a question
The answer is $2.50 because you do 145-132.50=12.5
Then you divide by 5 because that’s the difference between students then the final answer is 2.50
Answer:
42 child and 70 adult
Step-by-step explanation:
Let a = number of adult tickets
c = number of child tickets
a+c = 112
2.25a + 1.75c = 231
Solve the first equation for a
a = 112-c
Substitute this into the second equation
2.25(112-c) + 1.75c = 231
Distribute
252 - 2.25c +1.75c = 231
Combine like terms
252 -.5c = 231
Subtract 252 from each side
252-252 -.5c = 231-252
-.5c = -21
Divide each side by -.5
-.5c/-.5 = -21/ -.5
c = 42
Now can find a
a = 112-c
a = 112-42
a = 70