9.785
Take the formula for circumference of a circle, plug in your numbers, then divide by 2!
Answer:
≈ 12.6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x be the third side, then
x² + 6² = 14²
x² + 36 = 196 ( subtract 36 from both sides )
x² = 160 ( take the square root of both sides )
x = ≈ 12.6 ( to the nearest tenth )
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.