An angle measures 47°. What is the measure of its supplement?

The length of the west wall of fencing is 2x + 1 and the length of the North wall fencing is 2(2 x -1) write the full expression

marishachu [46]

Answer:

2x+1^2(2x-1)

Step-by-step explanation:

Brainliest if this helps

7 0

3 years ago

What is the coefficient of the term 13a in the expression 13a+6b? Please Help Fast alot of points

KATRIN_1 [288]

Answer:

13

Step-by-step explanation:

A coefficient is the contestant value (a number) placed before a variable to be multiplied. A coefficient is multiplied by it's neighboring variable. In '13a', 13 is being multiplied by a.

13 will be the coefficient in 13a.

3 0

3 years ago

Variable p is 2 more than variable d. Variable p is also 1 less than variable d. Which pair of equations best models the relatio

goldenfox [79]

If you would like to find a pair of equations that best models the relationship between p and d, you can do this using the following steps:

p is 2 more than d ... p = d + 2
p is 1 less than d ... p = d - 1

The correct result would be p = d + 2 and p = d - 1.

4 0

3 years ago

Read 2 more answers

What is the input value other than 7 for which g(x)=4

Vsevolod [243]

Given:

It is given that the value of the graph when the input 7 is $g(x)=4$

We need to determine the value of x when $g(x)=4$

Value of x when $g(x)=4$ :

The value of x can be determined by using the graph.

From the graph, we need to determine the value of x when $g(x)=4$ other than the value x = 7.

This can be determined by finding the point at which the line meets the point y = 4, we can find the corresponding x - value.

Thus, from the graph, it is obvious that the graph also meets the point y = 4 when x = -8.

Therefore, the input value is x = -8 which makes $g(x)=4$

Hence, the input value other than 7 for which $g(x)=4$ is x = -8.

7 0

3 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago