Answer:
V = 929.7
Step-by-step explanation:
Given the equation:
= 
The integral of the above equation is:
= 
Re-organizing the integrals:
= 
Integrating:
ln(CA) - ln(CA0) = 
Inputting the initial conditions of CA and the values of k and V0:
ln(7) - ln(100) = 
1.946 - 4.605 = -0.00286V
-2.659 = -0.00286V
=> V = 
V = 929.720
Approximating to one decimal place,
V = 929.7
Answer: a=3.74
Step-by-step explanation:
first use 15 to solve for x and z. x=7.5 and z=12.99 or 13. Once you know x you can use that to solve for y and a. y=6.5 and x=7.5 and using pythagorean theorem you will find that a= the square root of 14 or 3.74.
Answer:
![-\frac{3}{8} +\frac{\sqrt[]{23}i }{8},-\frac{3}{8} -\frac{\sqrt[]{23}i }{8}](https://tex.z-dn.net/?f=-%5Cfrac%7B3%7D%7B8%7D%20%2B%5Cfrac%7B%5Csqrt%5B%5D%7B23%7Di%20%7D%7B8%7D%2C-%5Cfrac%7B3%7D%7B8%7D%20-%5Cfrac%7B%5Csqrt%5B%5D%7B23%7Di%20%7D%7B8%7D)
or
Step-by-step explanation:
Bring the 8 to the left side so that we equal the equation to 0. To do this, simply substract 8 on both sides.
Where;
![Formula: x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=Formula%3A%20x%3D%5Cfrac%7B-b%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%20%20%7D%7B2a%7D)
Replace. Let x be r
![r=\frac{-3\frac{+}{}\sqrt[]{(3)^2-4(4)(2)} }{2(4)}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-3%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B%283%29%5E2-4%284%29%282%29%7D%20%20%7D%7B2%284%29%7D)
![r=\frac{-3\frac{+}{}\sqrt[]{9-32} }{8}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-3%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B9-32%7D%20%20%7D%7B8%7D)
![r=\frac{-3\frac{+}{}\sqrt[]{-23} }{8}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B-3%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B-23%7D%20%20%7D%7B8%7D)
It has no real solution because the square root is negative.
We can say that,
![r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}*\sqrt[]{-1} }{8}](https://tex.z-dn.net/?f=r%3D-%5Cfrac%7B3%7D%7B8%7D%20%5Cfrac%7B%2B%7D%7B%7D%5Cfrac%7B%5Csqrt%5B%5D%7B23%7D%2A%5Csqrt%5B%5D%7B-1%7D%20%20%7D%7B8%7D)
![r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}i }{8}](https://tex.z-dn.net/?f=r%3D-%5Cfrac%7B3%7D%7B8%7D%20%5Cfrac%7B%2B%7D%7B%7D%5Cfrac%7B%5Csqrt%5B%5D%7B23%7Di%20%7D%7B8%7D)
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