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Debora [2.8K]
3 years ago
10

How could Brent use a rectangle to model the factors of x2 – 7x 6?

Mathematics
2 answers:
otez555 [7]3 years ago
7 0

the correct answer is C

kvasek [131]3 years ago
3 0
<span>He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.</span>
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Solve the problem please!
Delvig [45]

Answer:

D Identity Property

Step-by-step explanation:

The identity property is whenever you multiply a number by one, it will always stay the same number.

4 0
3 years ago
Read 2 more answers
PROBLEM 1<br> What is the next term in the sequence -5, -1,3,7,...?
Romashka [77]

Answer:

the answer is 11

Step-by-step explanation:

each time you add 4

8 0
2 years ago
Graph f(x) = log5 (x-3).
Natali5045456 [20]

Step-by-step explanation:

We want to graph:

f(x) =\log_{5}(x - 3)

We first graph the parent function

g(x) =\log_{5}(x)

This parent function has x-intercept at (1,0) and it is asymptotic to the y-axis.

We then shift the graph of the parent function 3 units right, to obtain the graph of

f(x) =\log_{5}(x - 3)

The new x-intercept will be (4,0) and vertical asymptote will now be x=3.

See attachment.

6 0
3 years ago
18/90 in simplest form
mafiozo [28]
18/90
Divide by the common factor of 18 and 90, 9.
(18/9) / (90/9)
2/10
Divide top and bottom by 2

1/5

Hope this helps :)
7 0
3 years ago
Read 2 more answers
Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy
Alborosie

Answer:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

df = n-1=75-1 =74

The p value is:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

\bar X = 3.13 , s =0.03 , n =75

The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0
3 years ago
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