<span>(4^4)^2
= 4^(4*2)
=4^8
answer
4^8</span>
I believe it is 8,459,999,894,000,001
Answer: So lets say that the width is w. The length(L) is 4 meters greater than 3 times the width. 3 times the width would be 3w, and then 4 meters greater than that would be 3w+4. You have two widths and two lengths to a rectangle that must add up to equal 72. So 2w + 2L =72. But remember that one L equals 3w+4
2(w) + 2(3w+4) = 72
2w+6w+8=72
8w+8=72
8w=64
w=8
L=3w+4
L=3(8)+4
L=24+4
L=28
So the dimensions are 8 meters by 28 meters
To check 2(8)+2(28)=72
Answer:
Step-by-step explanation:
lets say "a" for the empty line,
for small triangle; y^2 = 2^2 + x^2
right triangle; we say a for empty line, a^2= 6^2 + x^2
and big triangle covering both triangles, 8^2 = y^2 + a^2
lets add left sides and right sides in each;
x^2 + 4 + x^2 + 36 + y^2 + a^2 = y^2 + a^2 + 64 and we can delete same things for both sides
y^2 and a^2 can be deleted and 4+36 - 64
2(x^2)=24
x^2= 12
and x will be √12
so, y^2 = x^2 + 2^2 which means y^2 = 12+4 y=16
