Answer:
The true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The sample mean is 
The population standard deviation is 
From the question we are told the confidence level is 92% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Generally the margin of error is mathematically represented as
=> 
=> 
Generally 92% confidence interval is mathematically represented as
=> 
=>
So the true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval
Answer:
The answer is 1,000
SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)
Answer:
B
Step-by-step explanation:
<h2>—Math</h2>
–x/4 < 7
–x < 28
x > –28
<em>follow </em><em>my </em><em>account^</em><em>^</em>
Answer:
15.9% of babies are born with birth weight under 6.3 pounds.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.8 pounds
Standard Deviation, σ = 0.5
We are given that the distribution of birth weights is a bell shaped distribution that is a normal distribution.
Formula:
P(birth weight under 6.3 pounds)
P(x < 6.3)
Calculation the value from standard normal z table, we have,
15.9% of babies are born with birth weight under 6.3 pounds.
