The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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Answer:
the second row is not a function! top row is a function
Step-by-step explanation:
because in order for it to be a function for every x there is exactly one y meaning there is no repeating x values! the second row had x = 5 twice, therefore they repeated x values meaning it's not a function
awwww..... that's what happens if you can't restrain yourself from judgment to one person . it will imprint on itself nor the sayings .
To
answer this item, we use the equation given for the calculation of the area of
the triangle.
A
= 0.5bh
Substituting
the known expressions,
A = (0.5)(3x – 6)(2x + 4)
Part
A: Use distribution method to simplify the expression for the calculation of
area.
A
= 0.5(6x^2 + 12x – 12x – 24)
A
= 0.5(6x^2 – 24)
<span> A
= 3x^2 – 12</span>
Part B: The equation for area of has a degree of two
because the highest exponent is 2.
<span>Part
C: The closure property of polynomials is always closed for multiplication.</span>
Answer:
0.1818...... and move the numbers backwards to the thousandth place
