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9966 [12]
3 years ago
9

Six times a number is greater than 20 more than that number. What are the possible values of that number?

Mathematics
1 answer:
Mariana [72]3 years ago
8 0
X > 4

Suppose that x is some number so 6 times a number is 6*x. 20 more than that number is 20 + x. If you put it together the inequality would be 6x > 20 + x. Subtracting x from both sides would result in 5x > 20. Dividing by 5 gives you x > 4 which is the final answer. So the possible values of that number is anything greater than 4.
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Step-by-step explanation:

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Which situation is most likely to have a constant rate of change
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Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body
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Answer:

The  position at time t  is  s(t) = 8t^2 -  14t   -8

Step-by-step explanation:

From the question we are told that

   The acceleration is  a =  16

   The velocity at t = 0  is  v(0) =  -14

    The  position at time t =  0  is s(0) =  -8

Generally acceleration is mathematically represented as

     a(t) =  \frac{d v}{dt }

=>   \frac{dv}{dt}  =  16

=>   dv  =  16 dt

integrating both sides we have    

     \int\limits dv  =  \int\limits16 dt

=>  v(t)  =  16 t  + c

Now at t = 0  

     v(0) =  16 * 0 +c  =  -14

=>  c =  -14

So

   v(t)  =  16 t  -14

Generally the position of the body is mathematically represented as

     s(t) =  \int\limits v(t)dt

So

    s(t) =  \int\limits 16t -  14  dt

So  

    s(t) = 16 \frac{t^2}{2} -  14t  + C

Now  at t =  0

     s(0) = 16 \frac{0^2}{2} -  14(0)  + C =  -8

=>    C =  -8

So

   s(t) = 8t^2 -  14t   -8

5 0
3 years ago
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