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3 years ago

9

The sum of three numbers is 123. The second number is 8 more than the first. The third number is 3 times the first. What are the

numbers ?
First number:

Second number:

Third number:

1 answer:

Aleksandr [31]3 years ago

5 0

Answer:

41 is my geuss

Step-by-step explanation:

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Construct the confidence interval for the population standard deviation for the given values. Round your answers to one decimal

Alex777 [14]

Answer:

The correct answer is " $2.633< \sigma < 4.480$ ".

Step-by-step explanation:

Given:

n = 21

s = 3.3

c = 0.9

now,

$df = n-1$

$=20$

⇒ $x^2_{\frac{\alpha}{2}, n-1 }$ = $x^2_{\frac{0.9}{2}, 21-1 }$

= $31.410$

⇒ $x^2_{1-\frac{\alpha}{2}, n-1 }$ = $10.851$

hence,

The 90% Confidence interval will be:

= $\sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}$

= $\sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }$

= $\sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }$

= $2.633< \sigma < 4.480$

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3 years ago

Use partial products to multiply 2,104 x 8. 2,104 32 8 x 4 ones 0 8 x 0 tens N 1 hundreds 8 x 2 thousands - 16.000

xeze [42]

9514 1404 393

Answer:

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Step-by-step explanation:

As your problem statement says, ...

2104 × 8 = 4×8 +00×8 +100×8 +2000×8

= 32 +0 +800 +16000

= 16,832

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Answer:

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