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34kurt
3 years ago
7

17. Julie has $80 in her savings account and plans to save Sr each

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0

Answer:

$8(x + 10)

Step-by-step explanation:

The expression $8x + $80  has two terms. They are $8x and $80.

When you factor an expression, you are looking for numbers that every term in the expression can divide by (and give a whole number).

Just by looking at the terms, you see they both have $ you can factor out. They can both also be divided by 8. This is called taking out a common factor.

$8x + $80     Take out the common factor

= ($8x) / $8 + ($80) / $8

= $8(x + 10)      The common factor goes outside the terms' bracket

This expression can't be factored more because there are no common factors. The binomial also doesn't have square numbers for example, which might make a case where you need to factor further with different methods.

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Now plug in your numbers.

This gives you root(7-1)^2+(5-(-3))^2.

Simplify to root(6)^2+(8)^2. Simplify again to root36+64.

Simplify one more time to root 100. now solve.

Your answer is 10.
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A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If
musickatia [10]

Answer:

a. The test statistic for this hypothesis would be z=1.71

b. Critical value at α = 0.10: z=1.282

c. Reject H0, the television network should not keep its current lineup.

d. H0: p ≤ 0.50; HA: p > 0.50

Step-by-step explanation:

We have to performa an hypothesis test on a proportion.

The claim is that the proportion of viewers that prefer the new show is bigger than 50% (meaning that most viewers prefer the new show).

The null hypothesis will state that both shows have the same proportion.

Then, the null and alternative hypothesis are:

H_0: \pi\leq0.50\\\\H_a: \pi>0.5

The sample proportion is p=0.53

p=X/n=438/827=0.53

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.5*0.5}{827}}= 0.017

Then, the z-statistic can be calculated as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.50-0.5/827}{0.017}=\dfrac{ 0.029 }{0.017} =1.706

The critical value for a right tailed test at a significance level of 0.10 is zc=1.282. This value can be looked up in a standard normal distribution table.

As the statistic is bigger than the critical value, it lies in the rejection region. The null hypothesis is rejected. There is evidence to support the claim that the proportion of viewers which support the new show is larger than 0.50.

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