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wel
4 years ago
5

Trigonometry - Verify Identity: cos (x - y) / sin (x + y) = 1 + cotxcoty / cotx + coty

Mathematics
1 answer:
IceJOKER [234]4 years ago
8 0

Answer:

The required verification is given below.

Step-by-step explanation:

To verify: \frac{\cos (x-y)}{\sin (x+y)}=\frac{1 + \cot x\cot y}{\cot x + \cot y}

Consider,

Left hand side = \frac{\cos (x-y)}{\sin (x+y)}

Now by using Trigonometric identities,

cos (A-B) = sin A.sin B + cos A.cos B \\sin (A+B) = sin A.cos B + cos A.sin B

Now we get,

Left hand side = \frac{\sin x\sin y + \cos x\cos y}{\sin x\cos y+\cos x\sin y}

Now dividing Numerator and Denominator by sin x.sin y we get

Left hand side = \frac{1 +\frac{\cos x\cos y}{\sin x\sin y} }{\frac{\sin x\cos y+\cos x\sin y}{\sin x\sin y } }

Now we have identity

cot x = \frac{\cos x}{\sin x}

and cot y =\frac{\cos y}{\sin y} then

Left hand side = \frac{1 +\cot x\cot y}{\cot x + \cot y}

Which is equal to our Right hand side required identity

This is the way we have

Left hand side = Right hand side   Proved.

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