They travel to school by picking the amount of conductions associated with the classmates. They travel with their belongings and bring them with them as they transport to their location (school). Once they get to school than they must place their belongings. The population is associated with global and significance. They will then conduct and the math teachers wont be worried.
(Brainliest will be appreciated) Thanks
10 pizzas in 60 minutes is how many he can make.
Answer:
1)(2m^2-4m)/2(m-2) = m (fourth blank)
2)m^2-2m+1/m-1= m-1 (second blank)
3)m^2-3m+2/m^2-m= (m-2)/m (first blank)
4)m^2-m-2/m^2-1=(m-2)/(m-1) (third blank)
Step-by-step explanation:
1)
(2m^2-4m)/2(m-2)
=[2m(m-2m)]/2(m-2)
= 2m/2
=m
2)
m^2-2m+1/m-1
= (m-1)^2/(m-1)
=(m-1)(m-1)/(m-1)
=(m-1)
3)
m^2-3m+2/m^2-m
=m^2-m-2m+2/m(m-1)
=m(m-1)-2(m-1)/m(m-1)
= (m-1)(m-2)/m(m-1)
=(m-2)/m
4)
m^2-m-2/m^2-1
=m^2+m-2m-2/(m+1)(m-1)
=m(m+1)-2(m+1)/(m+1)(m-1)
=(m+1)(m-2)/m+1)(m-1)
=(m-2)/(m-1) !
The general equation of a circle is

where a and b are the x and y components of the center respectively.
In order to get into this format, we have to use a method that I'm drawing a blank on the same, my apologies about that.
Anyway, what you want is to first isolate the variable on side so now you have:

(you'll see why I rearranged this soon)
Now you have to make it into an equation that can be simplified into the format stated earlier.
So, You have to take the x & y terms (-4x & -8y in this case) divide them each by two, and then square them.
The result of this step is the equation:
Notice the new components that have been added (4 & 16) and how the have been
added to both sides. That is an important step.
Now we simplify and get:

So the coordinate of the center is: (2,4) and the radius is 5