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2 years ago

Write an expression for h multiplied by 9 then evaluate that expression when h=3 full working out

Mathematics

2 answers:

Dimas [21]2 years ago

8 0

Answer:

9(3) = 27

Step-by-step explanation:

expression for h multiplied by 9

evaluate that expression when h=3

9(3) = 27

garri49 [273]2 years ago

3 0

Answer:

h=3

substitute 3 into h

9(3)=27

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Anestetic [448]

Answer:

3x - 6y = -12

x - 2y = -8

3x - 6y = -12

-3x +6y= 24

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inconsistent

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2 years ago

4. Describe the proportion method for solving a percentage problem:

kondor19780726 [428]

Step-by-step explanation:

Consider the provided information.

For the proportion method first set up the equation like this:

$\frac{Part}{Whole}=\frac{Percentage}{100}$

Perform the cross multiplication and then solve for the missing part.

For example:

Find 80 percentage of 10.

Step 1: Set up the equation.

$\frac{Part}{10}=\frac{80}{100}$

$\frac{Part}{10}=\frac{4}{5}$

Step 2: Perform the cross multiplication

$Part=\frac{4}{5}\times 10$

Step 3: Solve for the missing part.

$Part=4 \times 2$

$Part=8$

3 0

2 years ago

Read 2 more answers

Can some one help me

il63 [147K]

Answer:

5/6

Step-by-step explanation:

Dividing fractions:

Step 1: Rewrite the first fraction as it is.

Step 2: Replace the division sign with a multiplication sign.

Step 3: Flip the second fraction.

Step 4: Multiply the fractions and reduce the product if necessary.

Let's use the rule of dividing fractions on your problem.

Step 1: Rewrite the first fraction as it is.

$\dfrac{5}{8}$

Step 2: Replace the division sign with a multiplication sign.

$\dfrac{5}{8} \times$

Step 3: Flip the second fraction.

$\dfrac{5}{8} \times \dfrac{4}{3}$

Step 4: Multiply the fractions and reduce the product if necessary.

To multiply fractions, multiply the numerators together, and multiply the denominators together.

$\dfrac{5}{8} \times \dfrac{4}{3} = \dfrac{5 \times 4}{8 \times 3} = \dfrac{20}{24}$

We notice that the greatest common factor of 20 and 24 is 4, so we divide both the numerator and denominator by 4 to reduce the fraction.

$= \dfrac{4 \times 5}{4 \times 6} = \dfrac{5}{6}$

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3 years ago

Match the parts of an informational text with their definitions. PLS ANSWER!!!

Alexxx [7]

Answer:

1 e

2 c

3 d

4 a

5 b

Step-by-step explanation:

Hope this help

8 0

1 year ago

Find the solution of the given initial value problem: y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

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2 years ago