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3 years ago

A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs

Mathematics

1 answer:

ddd [48]3 years ago

5 0

40/3 days, (13.33 days)

Step-by-step explanation:

Set up the equation, 15/20 = 10/x, and then use cross mutiply to solve it.

10 * 20 = 15x, x = 200/15 = 40/3

Why?

b/c if each pig eats the same amount of food, then the ratio between the number of pigs and days should remain constant.

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The drama club sold 2100 tickets to their last play. Student tickets were $5 and adult tickets were $7. They collected $12,950.

worty [1.4K]

Answer:

875 student tickets were sold.

Step-by-step explanation:

Given:

The drama club sold 2100 tickets to their last play.

Student tickets were $5 and adult tickets were $7.

They collected $12,950.

Now, to find the number of student tickets sold.

Let the number student tickets be $x.$

And the number adult tickets be $y.$

So, the total number of tickets:

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Putting the value of $y$ from above:

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Subtracting both sides by 14700 we get:

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Dividing both sides by -2 we get:

$x=875.$

The number of student tickets = 875.

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3 years ago

A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs​

A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs