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bezimeni [28]
3 years ago
10

If 3x-y=123x−x=123, x, minus, y, equals, 12, what is the value of \frac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscript

, x, end superscript, divided by, 2, start superscript, y, end superscript, end fraction
Mathematics
1 answer:
nlexa [21]3 years ago
3 0

Answer:

\frac{8^x}{2^y} = 4096

Step-by-step explanation:

Rules:

  1. \frac{a^m}{a^n}=a^{m-n}
  2. a^m\times a^n= a^{m+n}
  3. (a^m)^n=a^{m\times n}

Given that,

3x-y =12

Therefore

\frac{8^x}{2^y}

=\frac{(2^3)^x}{2^y}  [ since 8=2^3 ]

=\frac{2^{3x}}{2^y}   [ applying 3rd rule]

=2^{3x-y} [ applying 2nd rule]

=2^{12}   [ since 3x-y =12]

=4096

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lukranit [14]

The correct value of this equation is <u>m = </u><u>24</u>

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the <u>term 4</u>. Therefore, we will multiply the sides by <u>4</u>:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

<u>m = 24</u>

Therefore, the correct value of this equation will be <u>m = 24</u>

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1 year ago
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NNADVOKAT [17]

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2 years ago
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3 years ago
What is 6,010,499,999 rounded to the nearest billion?
aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

Given the following question:

6,010,499,999

<u>Find the billions place value:
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<u>Round to the nearest billion:</u>
6,010,499,999
0
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Your answer is "6000000000."

Hope this helps.

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