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Verdich [7]
3 years ago
12

Compare 6 ⋅ 108 to 3 ⋅ 106.

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

Option B.

Step-by-step explanation:

The given numbers are 6\cdot 10^8 and 3\cdot 10^6.

Let 6\cdot 10^8 is x times larger than 3\cdot 10^6.

x\times 3\cdot 10^6=6\cdot 10^8

Divide both sides by 3\cdot 10^6.

x=\dfrac{6\cdot 10^8}{3\cdot 10^6}

x=2\cdot \dfrac{10^8}{10^6}

Using the property of exponent, we get

x=2\cdot 10^{8-6}             (\because \dfrac{a^m}{a^n}=a^{m-n})

x=2\cdot 10^2

x=2\cdot 100

x=200

6\cdot 10^8 is 200 times larger than 3\cdot 10^6.

Therefore, the correct option is B.

djverab [1.8K]3 years ago
4 0

Answer:

6*10^8  is 200 times larger than  3*10^6

Step-by-step explanation:

6*10^8\ and \ 3*10^6

To compare both values we divide the exponents

\frac{6*10^8}{3*10^6}

6 divide by 3 is 2

for simplify exponents we use exponential property

a^m / a^n = a^(m-n)

\frac{10^8}{10^6}=10^2

\frac{6*10^8}{3*10^6}=2*10^2= 200

6*10^8  is 200 times larger than  3*10^6

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Answer:

This is an example of a combined 45 45 90 triangle and a 60 30 90 triangle. I have put the pictures showing the side lengths.

Step-by-step explanation:

On the 30 60 90, the hypotenuse is 6.

6 = 2x

x = 3

therefore, the two legs of the triangle are measured as 3 and 3\sqrt3}

Now that we have  3\sqrt3} as one of the legs for the other triangle, using the picture of the 45 45 90 triangle, the hypotenuse must be x\sqrt{2}.

Since x =  3\sqrt3x},    x\sqrt{2} is 3\sqrt3} x

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3 years ago
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vivado [14]

Answer:

Part 1) Vertical line : x=1

Part 2) Horizontal line :  y=-4

Step-by-step explanation:

Part 1) Write the equation for the vertical line passing through the point (1,-4)

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so

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therefore

The equation of the line is

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8 0
4 years ago
7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and
Juliette [100K]

Answer:

A) JK and AB =

[tex] \boxed{( \theta) = \f{12}{( \theta)} } So, =》 \dfrac{10}{5} = \dfrac{1}{ \( \theta) } =》 \( \theta) = \dfrac{5}{2}[/tex]

B) AABC

[tex] \boxed{( \theta) = {1}{( \theta)} } So, 23}{-18=\\Ans } \boxed

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[tex] e \fbox{: } The value of k for which \sin(jm) = \cos(x) is \dfrac{\p}{2} ans[/tex]

----------

3 0
3 years ago
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melamori03 [73]

Answer:

#6:

A: m=-\frac{2}{5}

Step-by-step explanation:

Points: (3, -5) and (-7, -1)

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m = \frac{-5+1}{3-(-7)}

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Sauron [17]

Answer:

If the equation is 3x^2+6y^2, when x=0 and y=2.

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So, 0+6(4)= 24

Therefore, the answer is 24.

Step-by-step explanation:

8 0
3 years ago
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