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Verdich [7]
3 years ago
12

Compare 6 ⋅ 108 to 3 ⋅ 106.

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

Option B.

Step-by-step explanation:

The given numbers are 6\cdot 10^8 and 3\cdot 10^6.

Let 6\cdot 10^8 is x times larger than 3\cdot 10^6.

x\times 3\cdot 10^6=6\cdot 10^8

Divide both sides by 3\cdot 10^6.

x=\dfrac{6\cdot 10^8}{3\cdot 10^6}

x=2\cdot \dfrac{10^8}{10^6}

Using the property of exponent, we get

x=2\cdot 10^{8-6}             (\because \dfrac{a^m}{a^n}=a^{m-n})

x=2\cdot 10^2

x=2\cdot 100

x=200

6\cdot 10^8 is 200 times larger than 3\cdot 10^6.

Therefore, the correct option is B.

djverab [1.8K]3 years ago
4 0

Answer:

6*10^8  is 200 times larger than  3*10^6

Step-by-step explanation:

6*10^8\ and \ 3*10^6

To compare both values we divide the exponents

\frac{6*10^8}{3*10^6}

6 divide by 3 is 2

for simplify exponents we use exponential property

a^m / a^n = a^(m-n)

\frac{10^8}{10^6}=10^2

\frac{6*10^8}{3*10^6}=2*10^2= 200

6*10^8  is 200 times larger than  3*10^6

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If 20 divided by 5 = 4 <br> Then 20 divided by 5.5=4.?
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3 years ago
with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line y=x A student determined one of the vertices on the im
pochemuha
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Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .
Masja [62]

Answer:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

Step-by-step explanation:

Lets   y  =  f(x)   in a cartesian coordinates

Having three zeros:

x = -3       ⇒   x  = -2      ⇒   and   x = 1  

That meas that if   x  takes the above mentioned  values " y " must be zero

therefore  y  must be of the form

f (x)  =  y  =  ( x + 3 ) *  ( x +  2 ) * ( x - 1 )     (1)

In that case for y to be zero one of the factors should be zero or

y  =  0        x  + 3 = 0    and  x = - 3  is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x =  3 ,  y have to be 11, therefore we plug in equation (1)  that value to see what happens

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )

11  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1)   =  6*5*2  = 60

Then we adjust the expression (1) to meet the condition of the function passing through point  ( 3 , 11) as:

y  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60    (2)

and check to see if we did right

for y to be zero      x   can be    x = - 3    x  =  -2   and  x = 1 in all these cases y = 0.  And if  x  =  3   in equation (2)  y = 11. And that what we want to shown. Then the solution is:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

8 0
3 years ago
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