HELP ASAP

I need help on this.

mote1985 [20]

Let's go:

7 = x

38 + x = 180

x = 180 - 38

x = 142°

7 = 142°

I hope I helped you

5 0

3 years ago

Sydney needs $450 to buy a TV for her room.she already saved $50. She earns $20 an hour at her job.set up and solve an equation

Rudik [331]

20x+50=450
-50 -50
20x=400
Divide both sides by 20
X=20

8 0

3 years ago

How to find MP when discount percent and SP are given

nadezda [96]

Given:

Consider the discount percent and SP are given.

To find:

The MP.

Solution:

Let x% be the discount percent Then

$SP=MP-x\%\text{ of }MP$

$SP=MP-\dfrac{x}{100}MP$

$SP=\left(1-\dfrac{x}{100}\right)MP$

$SP=\left(\dfrac{100-x}{100}\right)MP$

Multiply both sides by 100.

$100SP=(100-x)MP$

Divide both sides by $(100-x)$ .

$\dfrac{100}{100-x}SP=MP$

Therefore, the formula for MP is $MP=\dfrac{100}{100-x}SP$ , where x is the discount percentage.

7 0

3 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574$

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0

3 years ago

Volume & surface! May I please have help

Ludmilka [50]

Answer:

D

Step-by-step explanation:

surface area of cylinder

=(area of base)×2 + (area of curved surface)

$=(\frac{20}{2} )^{2} \pi$ × 2 + $20\pi$ × 25