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3 years ago

Hiiiiii i need help

Mathematics

2 answers:

hodyreva [135]3 years ago

8 0

The answer is 8&3 5&2. That’s the consecutive interior angles

elena55 [62]3 years ago

7 0

Answer:

3 goes with 8 and 5 goes with 2

Step-by-step explanation:

I hope this helps!

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URGENT!!!!!!!! PLEASE HELP ASAP TIMED!!!!!!!!!!!!!!!

barxatty [35]

Step-by-step explanation:

Given that,

Perpendicular = 17 units

Hypotenuse = 25 units

We need to find the value of x.

Using Pythagoras theorem to find x.

Hypotenuse² = base²+perpendicular²

25² = x² + 17²

x = 18.3 units

So, the value of x is equal to 18.3 units. No, the sides do not form a Pythagorean triplet.

4 0

3 years ago

Please help me with this question. I don’t understand how to do this.

Blizzard [7]

Answer:

133/152

Step-by-step explanation:

The probability of 2 independent events is the product of the individual events. Independent means the first event has no effect on the probability of the second event. Since we are replacing the first marble, the first even has no effect on the probability of the second event.

There are 48 total marbles

Let A = pulling a blue marble

Let B = pulling a red marble

P(A) = 14/48

P(B) = 19/48

and

P(A then B) = (14/48)(19/48) = 266/2,304 = 133/1,152

8 0

3 years ago

Match the parabolas represented by the equations with their foci.

Elenna [48]

Function 1 $f(x)=- x^{2} +4x+8$

First step: Finding when $f(x)$ is minimum/maximum
The function has a negative value $x^{2}$ hence the $f(x)$ has a maximum value which happens when $x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2$ . The foci of this parabola lies on $x=2$ .

Second step: Find the value of y-coordinate by substituting $x=2$ into $f(x)$ which give $y=- (2)^{2} +4(2)+8=12$

Third step: Find the distance of the foci from the y-coordinate
$y=- x^{2} +4x+8$ - Multiply all term by -1 to get a positive $x^{2}$
$-y= x^{2} -4x-8$ - then manipulate the constant of y to get a multiply of 4
$4(- \frac{1}{4})y= x^{2} -4x-8$
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is $12- \frac{1}{4}=11.75$

Hence the coordinate of the foci is (2, 11.75)

Function 2: $f(x)= 2x^{2}+16x+18$

The function has a positive $x^{2}$ so it has a minimum

First step - $x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4$
Second step - $y=2(-4)^{2}+16(-4)+18=-14$
Third step - Manipulating $f(x)$ to leave $x^{2}$ with constant of 1
$y=2 x^{2} +16x+18$ - Divide all terms by 2
$\frac{1}{2}y= x^{2} +8x+9$ - Manipulate the constant of y to get a multiply of 4
$4( \frac{1}{8}y= x^{2} +8x+9$

So the distance of focus from y-coordinate is $\frac{1}{8}$ to the north of $y=-14$
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: $f(x)=-2 x^{2} +5x+14$

First step: the function's maximum value happens when $x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25$
Second step: $y=-2(1.25)^{2}+5(1.25)+14=17.125$
Third step: Manipulating $f(x)$
$y=-2 x^{2} +5x+14$ - Divide all terms by -2
$-2y= x^{2} -2.5x-7$ - Manipulate coefficient of y to get a multiply of 4
$4(- \frac{1}{8})y= x^{2} -2.5x-7$
So the distance of the foci from the y-coordinate is - $\frac{1}{8}$ south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when $x=8.5$ and $y=79.25$ . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when $x=-2.75$ and $y=-10.125$ . Manipulating coefficient of y, the distance of foci from y-coordinate is $\frac{1}{8}$ to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when $x=1.5$ and $y=9.5$ . The distance of the foci from the y-coordinate is $\frac{1}{8}$ to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0

3 years ago

Una página de plástico diseñada para guardar cromos puede contener hasta 9 cartas. ¿Cuántas páginas se necesitarán para almacena

adelina 88 [10]

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´

<h3>¿Cuántas páginas se necesitarán para almacenar 517 tarjetas? </h3>

Sabemos que cada página puede almacenar hasta 9 cartas.

Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.

N = 517/9 = 57.44

Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.

Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.

Sí quieres aprender más sobre cocientes:

brainly.com/question/3493733

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8 0

1 year ago

Find a 95% confidence interval for the difference in proportions, pt-po, two ways, using StatKey or other technology and percent

beks73 [17]

A bit confusing for me to be able to answer this for you… any way you can simplify your question?

4 0

3 years ago